Unit 6 Stoichiometry - Central Dauphin School District
percent yield 2013 answers.notebook
February 28, 2013
Unit 6 Stoichiometry Percent Yield
Steps for finding PERCENT YIELD: 1. Balance the chemical equation 2. Find the limiting reactant 3.Find the theoretical yield 4.Find the actual yield 5.Find the percent yield
1
percent yield 2013 answers.notebook
February 28, 2013
% yield = mass Actual Yield
X 100%
mass Theoretical Yield
*The actual yield is often given in the problem...is occasionally referred to
as the experimental yield.
*The theoretical yield is determined by solving a problem using the
stoichiometry map, usually a 3step
gramgram problem.
maximum amount of product that could possibly form
PERCENT YIELD
Theoretical yield
Used to help you figure out where to put the compounds in a 3step stoich problem
L 7
needed to do a stoichiometry problem
amount of product that forms
experimentally in the lab
actual yield
reactant used to determine the theoretical yield
Limiting Reactant
Balanced Equation
this step uses coefficients from balanced equation
mole ratio
2
percent yield 2013 answers.notebook
February 28, 2013
Nitrogen dioxide, NO2 , can be converted to dinitrogen pentoxide, N2O5 , by reacting it with ozone, O3 .
2NO2(g) + O3(g)
N2O5(s) + O2(g)
Calculate the percent yield for a reaction in which 0.38 g of NO2 reacts with excess O3 and 0.36 g of N2O5 is recovered.
theoretical yield = actual yield =
% yield = mass Actual Yield X 100%
mass Theoretical Yield
theoretical yield = 0.45g actual yield = 0.36 g
% yield =
X 100%
3
percent yield 2013 answers.notebook
February 28, 2013
packet:
1. Determine the percent yield for the reaction between 3.74 g Na and excess O2 if 5.34 g of Na2O2 is recovered.
balanced equation:
% yield =
X 100%
Mass in grams
L
(a) Mass of watch glass
61.19 g
A
(b) Mass of watch glass + potassium iodide
62.01g
B
(c) Mass of potassium iodide b a
0.82 g
(d) Mass of watch glass
61.19 g
D
(e) Mass of watch glass + lead nitrate
62.38 g
A
(f) Mass of lead nitrate e a
1.19 g
T
(g) Mass of filter paper
(h) Mass of filter paper and precipitate PbI2 after dried*
1.09 g
A
2.10 g
(i) Mass of precipitate after dried* also referred to as the experimental yield h g
1.01 g
4
percent yield 2013 answers.notebook
February 28, 2013
2. In this reaction, one of the reagents was a limiting reagent. Using your knowledge of chemical equations and limiting reagents, determine which was the limiting reactant for this experiment.
Use (c) from the data table and (f) from the data table to do a 3step LR problem.
0.82 g KI
PbI2
PbI2 PbI2
1.19 g Pb(NO3)2
PbI2
PbI2
PbI2
3. Using the LR from #2, write down the theoretical yield of PbI2
% yield = mass Actual Yield
X 100%
mass Theoretical Yield
5
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