37 hcl molarity
[DOC File]MOLARITY / CONCENTRATION
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The final molarity is given by the expression. If 50.00 mL of 0.100 M HCl are added to 100.00 mL of 0.400 M HCl and the mixture is diluted to a final volume of 500.00 mL, the final molarity will be. Solution 1 (0.100 M HCl)(0.05000 L) = 5.00x10-3 mol HCl. Solution 2 (0.400 M HCl)(0.1000 L) = 4.00x10-2 mol HCl. Total moles = 4.50x10-2 mol HCl ...
[DOC File]Solutions Worksheet #1 (Solutions, Electrolyte’s, and ...
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If 0.37 grams of potassium hydroxide are added to enough water to make 0.020L of solution, what is its molarity? 5. When 153 grams of a soluble compound are added to enough water to make 0.575L of solution the molarity of the solution is known to be 2.50 M.
[DOC File]Dilutions Worksheet
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7) How much 0.05 M HCl solution can be made by diluting 250 mL of 10 M HCl? 8) I have 345 mL of a 1.5 M NaCl solution. If I boil the water until the volume of the solution is 200 mL, what will the molarity of the solution be? 9) How much water would I need to add to 500 mL of …
[DOC File]CONCENTRATION UNITS
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What is the molarity, molality and mole fraction of HCl? Begin with the assumption of 100 g of solution. With this assumption, you now know a few other facts. In 100 g of solution, 37.0 g is due to HCl (grams of solute) and 63.0 g is due to water (grams of solvent). To find molarity, we need to determine the moles of HCl (solute) per liter of ...
[DOC File]Ch. 10-12 problems.docx
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The equation for molarity states that the molarity of a solution is equal to the number of moles of solute divided by the number of liters of solution. In the first solution, the molarity will clearly be equal to 1.0M because there are 1.0 moles of NaCl and a solution volume of 1.0 L.
[DOC File]Solutions Worksheet #1 (Solutions, Electrolyte’s, and ...
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Molarity of Ions in Solution. Calculate the molarity of the ions in the following solutions: 0.917M aluminum sulfate. 1.25M aluminum chloride. Dilutions. If 30.0 mL of 12.0 M HCl stock solution are diluted to a volume of 500. mL, what is the molarity of the dilute solution?
[DOC File]Acid-Base Titration
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5. Calculate the molarity (M) of HCl used in the titration of a 0.2239-g sample of sodium . carbonate that required 39.01 mL of the titrant (HCl) to reach the second equivalence point. Titration of Sodium Carbonate with Hydrochloric Acid. Objectives: In this experiment, a solution of Na2CO3 will be titrated with a solution of HCl.
[DOC File]Chapter 1 - Solutions
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84) Calculate the concentration (in molarity) of an NaOH solution if 25.0 mL of the solution is needed to neutralize 17.4 mL of a 0.312 M HCl solution. The neutralization reaction is. HCl + NaOH ( NaCl + H2O . Moles NaOH = 0.0174 mL HCl soln 0.312 mol HCl 1 mol NaOH = 5.429 x 10-3 mol . L soln 1 mol HCl
[DOC File]Chemistry Worksheets
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3) When hydrogen chloride reacts with ammonia, ammonium chloride is formed. Write the equation for this process, and indicate which of the reagents is the Lewis acid and which is the Lewis base. 4) Write an equation for the reaction of potassium metal with hydrochloric acid.
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What will be the molarity of the resulting solutions made by mixing the following? Assume that volumes are additive. (a) 175 mL of 3.0 . M . H2SO4 with 275 mL of H2O… (c) 50.0 mL of 0.250 . M . HCl with 25.0 mL of 0.500 . M . HCl. 24. Calculate the volume of concentrated reagent required to prepare the diluted solutions indicated: (a) 18 . M
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