Chain rule calculus

    • Chain Rule Examples - Calculus How To

      Chain Rule - Examples . Chain Rule of Differentiation . Graphing a Composite Function . Hassell's Model . Several examples are presented below to demonstrate the chain rule. Examples show the basic differentiation and applications to extrema in graphing.

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    • [DOC File]AP CALCULUS AB

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      Using the chain rule, Notice that we used the General Power Rule and, in the last step, we took the derivative of the argument. Multimedia Links. For an introduction to the Chain Rule (5.0), see Khan Academy, Calculus: Derivatives 4: The Chain Rule (9:11).

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    • [DOC File]THE CHAIN RULE or FUNCTION OF A FUNCTION …

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      THE CHAIN RULE. Suppose we have the function . Before today, the only way that you would know how to differentiate the function is to perform algebra and then take the derivative. However, we could think of as a composition of functions. Another way to look at this is Leibniz notation… This brings us to our main event.. THE CHAIN RULE

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    • [DOC File]Math 121 - Calculus for Biology I

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      The Chain Rule will be used to find derivatives of composite functions. There are two definitions for the chain rule, both mean the same thing: If y is a function of u (y = f(u)) and u is a function of x (u = g(x)), than y = f(u) = f(g(x)), and : OR. If y = f(g(x)), than . Example 1: Find if . Example 2: (Product and Chain Rules) If find ...

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    • [DOC File]The Chain Rule

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      Chain Rule Notes. Chain Rule. The derivative of is . 1. 2. 3. 4. Title: AP Calculus AB Author: Central Bucks SD Last modified by: ROBINSON, JENNIFER

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    • [DOC File]AP Calculus AB

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      Chain Rule from Calculus 1: A Review. Let . w = f(x), where f is a differentiable function of x. Suppose also that . x = g(t). Sketch a diagram for the composition of the functions: w = f(g(t)). Theorem: Let . w = f(x), where f is a differentiable function of x, and suppose that . x = g(t) is a differentiable function of t.

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    • [DOC File]Chain Rule

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      In fact the “chain” can be as long as we please . dy = dy × dt × du × dv. dx dt du dv dx. Consider this example: Suppose y = (x3 + 5x)7. let y = t7 and t = x3 + 5x. so dy = 7t6 and dt = 3x2 + 5. dt dx. substituting in dy = dy × dt

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