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[DOCX File]Stoichiometry - Difficult problems
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2 C8H18(g) + 25 O2(g) -----> 16 CO2(g) + 18 H2O(g) + 10,900 kJ. How many liters of air must react with 1.000 L of isooctane in order for combustion to occur completely? At 20. degrees . Celcius, the density of isooctane is 0.6916 g/ mL, and the density of oxygen is 1.331 g/L. (Hint: remember to use the percentage of oxygen in air.) 8.
convert g l to mol l

[DOC File]Practice Problems for Concepts Chemical Equilibrium
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CO(g) + H2O (g) ↔ CO2 (g) + H2 (g) If a 10.00L vessel has 2.50 mol CO2 and H2O, and 5.00 mol CO2 and H2 gas at 588°K, which way will the reaction proceed? (Kc = 31.4 at 588°K) What are the concentrations of all species at equilibrium? What is the pH of a solution containing 50.0mL of 1.00M HCl and 100.0mL of 0.25M HCl?
g ml to g m3

[DOC File]Sample Lab Report: Molar Volume Of Hydrogen
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One mole x 2.02 g/mol. 22.5 L = 0.0897 g/L . published value = 0.0899 g/L . Dang! Hydrogen is a really light gas. Perhaps that’s why they used it in Zeppelins. And yes, it is way cheaper than helium. In setting up the experiment a student noticed that a bubble of air leaked into the graduated cylinder .
convert g l to g ml

[DOC File]17
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Now we convert the solubility in mol/L to g/L: 4.90 ( 10(3 ( = 0.67 g/L. 17.2 Solubility and the Common-Ion Effect. Learning Objectives. Explain how the solubility of a salt is affected by another salt that has the same cation or anion (common ion). Calculate the solubility of a slightly soluble salt in a solution of a common ion. (Example 17.5)
grams ml to g l

[DOC File]Name:
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C3H7COOH(l) + 5O2(g) ( 4CO2(g) + 4H2O(l) (Hc = (2183.6 kJ/mol 7 The reaction of magnesium with sulfuric acid was carried out in a calorimeter. This reaction caused the temperature of 55. grams of liquid water, within the calorimeter, to raise from 1.0(C to 28.(C. Calculate the …
g ml to g liter

[DOC File]Glutaraldehyde fixation protocol
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? g * 137.99 g/mol = g mol/L. 137.99 g/L * 0.1L (100 mLs) = 13.799. Add 13.8 grams in 100 mLs H20 or 41.4 g dissolved into water to equal 300 mLs. 2% glutaraldehyde in 0.1 M phosphate buffer. Glutaraldehyde comes in 50% solution in 10 mLs. 10 mLs glutaraldehyde + 240 mLs phosphate buffer = …
mg l to mol l

[DOC File]AP Chemistry
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11.5 L x 3.48 g/1 L x 1 mol/32.0 g = 1.25 mol O2 1.34 mol Fe x 2 mol Fe2O3/3 mol Fe = 0.670 mol Fe2O3. 1.25 mol O2 x 2 mol Fe2O3/3 mol O2 = 0.833 mol Fe2O3 0.670 mol Fe2O3 x 160 g Fe2O3/1 mol Fe2O3 = 107 g Fe2O3 35 0.250 L x 0.127 mol/1 L x 74.1 g/1 mol = 2.35 g
convert g mol to mol

[DOC File]Chapter 13 worksheet #1
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Assume that you have 1 L of solution: Mass of water = mass of solution – mass of NaOH = 1000 g – (0.300 mol)(40 g/mol) = 1000 g – 12 g = 988 g. Molality = 0.300 mol/0.988 kg = 0.304 m. Notice that the molality is a little bigger than molarity. Why are these two numbers similar and why is molality always greater than molarity?
g ml to mol l

[DOC File]Equilibrium Worksheet
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Phosphorus pentachloride decomposes to phosphorus trichloride and chlorine gas. A 1.10 mol/L sample of PCl5 was placed into a vessel. At equilibrium it was determined that the concentration was 0.33 mol/L. Calculate the Keq for this reaction. PCl5(g) ⇌ PCl3(g) + Cl2(g) MR 1 1 1 I 1.10 0 0 C -x +x +x E 1.10-x =0.33 x x x= 0.77
convert g l to mol l

G l to g mol