Kj kg to m2 s2

    • [DOC File]California State University, Northridge

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      The one exception to be aware of is the computation of kinetic energy per unit mass as V2/2. If the velocity is in m/s, V2/2 will have units of m2/s2 which is equivalent to J/kg. Your answer must be divided by (1000 J/kJ) to get an answer in kJ/kg. Typical engineering units have energy terms in Btu, pressures in lbf/in2 (psia), and volumes in ft3.

      m 2 s 2 to kj kg


    • Honors Chemistry Worksheet on Electronic Structure of the …

      It is usually expressed in units of kJ/mol. Given that; R, the Rydberg constant, is 1.097 x 107 m-1. h, Planck’s constant, is 6.6262 x 10-34 J-s. c, the speed of light, is 2.998 x 108 m s-1. calculate from these data the ionization energy of hydrogen in kJ/mol. Compare the results of your calculation with an accepted value. 1/λ = R (1/nf2 ...

      kj kpa to m 3


    • [DOC File]Dynamics - Bergen

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      J = (kg–m / s2) - m. J = N-m = kg-m2 / s2. Example 1: A constant force of 45 N is applied to a mass on a frictionless surface. The force is applied in the same direction as the motion of the object. How much work does that force do over a distance of 6.0m?

      m 2 s 2 to kj


    • [DOC File]Chapter 5

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      Qsur +89.2 kJ/kg ( S)sur 0.255 kJ/kgK 0.019 kJ/kgK. Prob : 5.10 A turbine operating at steady state receives air at a pressure of p1 3.0 bar and temperature of 390 K. Air exits the turbine at a pressure of p2 1.0 bar. The work developed is measured as 74 kJ/kg of air flowing through the turbine.

      m 2 s 2


    • [DOC File]California State University, Northridge

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      misi = m2s2 or si = s2 since mi = m2. We can use the result that s2 = si to determine the final state for maximum work. Since we know that P2 = 200 kPa and s2 = si = s(1.2 MPa, 350 C) = 7.2139 kJ/kg·K (h=3154.2 kJ/kg for this inlet state) the final state at 200 kPa is found to be between the saturated vapor and a temperature of 150oC.

      kj kg to m s


    • CHEM 1411 Exam #2

      R = 8.314 J/K.mol 1J = 1 Kg. m2/ s2 . BONUS question-Show all your work.(10 points) Using Hess’s law of constant heat of summation and given: I) H2O(l) ( H2O(g) ∆H = (44.1 kJ. II) CH3COCH3(l) + 4O2(g) ( 3CO2(g) + 3H2O(l) ∆H = (1787 kJ

      kpa to kj kg


    • [DOC File]SK ACADEMY|ENGINEERING TUITION,GATE …

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      At 30 bar, 400°C : h1 = 3230.9 kJ/kg, s1 = 6.921 kJ/kg K = s2 = s3, At 5 bar :sf = 1.8604, sg = 6.8192 kJ/kg K, hf = 640.1 kJ/kg. Since s2 > sg, the state 2 must lie in the superheated region. From the table for superheated steam. t2 = 172°C, h2 = 2796 kJ/kg. SK Engineering Academy. 35 ME 2202 Engineering Thermodynamics Mechanical Engineering ...

      kg m 2 s 3


    • [DOC File]AP Chemistry Packet

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      a) 1 kg m2/s2 b) 2 kg c) 4.184 cal d) 1 g cm/sec e) none of these 3. An 35.0 mg object must be moving at a speed of ___ km/hr in order to posses a KE of 1.20 J.

      kpa m3 to j


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