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Select W18 x 55 with bMn = 345 k-ft. for Lb = 12 ft. and Cb = 1.0. For Cb = 1.37, bMn = 345 x 1.37 = 472.65 k-ft. but must be ≤ bMp = 420 k-ft. Therefore, for Cb = 1.37, bMn = 420 k-ft., which is < Mu (421.44 k-ft), (NOT OK!) Select W 21 x 55 with bMn = 388 k-ft. for Lb = 12 ft. and Cb = 1.0
kip ft to lbs inch

[DOC File]Lecture 3-1 STUDENT MASTER COPY
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= (1.929 ft) (15.00 lb) (2.298 ft) (25.98 lb) = 30.77 lb ft. Mb = (30.77 lb ft) k. Sample Problem 3.4 - A rectangular plate is supported by brackets at . points A and B and by a wire CD between points C and D as shown. If the tension in the wire is 200 N, determine the moment about A of the force exerted by the wire at point C. Solution: Ma ...
kip ft to lb ft

[DOCX File]California State Polytechnic University, Pomona
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= 0.94 kJ/kg · K. Neglecting potential energy effects, determine the rate of heat transfer to the carbon dioxide, in kW. 56.1 kW. 8 . Steam enters a well-insulated nozzle at 300 lbf/in.2, 600°F, with a velocity of 100 ft/s and exits at 40 lbf/in.2 with a velocity of 1800 ft/s.
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[DOC File]EGR 280 – Mechanics Problem Set 1 - Oakland University
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If θ = 30°, determine the stiffness k of the spring so that the rod is in equilibrium. Ans: k = 11.2 lb/ft. 3.7 . Determine the distance d for placement of the load P for equilibrium of the smooth bar in the position θ as shown. Neglect the weight of the bar.
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[DOC File]Chapter 2
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*7-39. A 96-lb block rests on a table where (k = 0.4. A cord tied to this block passes over a light frictionless pulley. What weight must be attached to the free end if the system is to accelerated at 4 ft/s2? F = (kN = 0.2 (96 lb); F = 19.2 lb. W – 19.2 lb = 12 lb + 0.125 W; W = 35.7 lb…
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[DOC File]FORMULA SHEET - Homestead
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hp = lb x fpm / 33,000 hp = ft-lb x rpm / 5,252 kW = hp x 0.7457 hpMetric = hp x 1.0138 Horsepower as defined by Watt, is the same for AC and DC motors, gasoline engines, dog sleds, etc. Horsepower and Electric Motors . Torque = force x radius = lb x ft = T Speed = rpm = N Constant = 5252 = C HP = T x N / C
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[DOCX File]University Of Maryland
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An inexhaustive list of Agricultural Nutrient Management Relationships. fertilizer. 1 unit weight of P. 2 O: 5 = 0.44 weight of P in P. 2 O 5 (units don’t matter; 1 g P 2 O 5 = 0.44 g P; 1 lb P 2 O 5: = 0.44 lb P) . 1 unit weight of K. 2: O = 0.83 weight of K in K. 2: O (as above, units don’t matter; they just …
kips to ft lbs torque

[DOC File]Chapter 2
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K = ½mv2 = ½(75 slugs)(80.66 ft/s)2; K = 244,000 ft lb. 9-3. A 2500-kg truck traveling at 40 km/h strikes a brick wall and comes to a stop in 0.2 s. (a) What is the change in momentum? (b) What is the impulse? (c) What is the average force on the wall during the crash?
lb ft to kip in

[DOC File]Set #1 - CCSF
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4. Determine the moment about the origin O of the force F = – (1.5lb)i + (3lb)j –(2lb)k which acts at a point A. Assume that the position vector of A is . a) r = (2.5ft)i – (1ft)j + (2ft)k. b) r = (4.5ft)i – (9ft)j + (6ft)k. c) r = (4ft)i – (1ft )j + (7ft)k. Answer: a) Mo= ( - 4i + 2j + 6k ) ft-lb. b) Mo= (0i – 0j - 0k ) ft-lb
kip ft to lbs inch

Lb in to k ft