Molarity calculator ml
[DOC File]Chapter 13 worksheet #1
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What is the molarity of an ammonium carbonate solution if the concentration of ammonium ions is 2 M? What is the concentration of carbonate ions and what is the total concentration of solute particles? [CO32-] = 1M [particles] = 3 M. A solution was made by dissolving 800.0 g of NaOH in 2.00 L of water. Calculate the molality, mole fraction ...
[DOC File]Conductivity Versus Concentration
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A series of solutions are prepared by diluting 10.0 mL, 20.0 mL, 30.0 mL, 40.0 mL, and 50.0 mL of a 1.00x10-2 M CaCl2 solution each to 100.0 mL. Calculate the molarity of each solution. Record these values in the Data Table before you come to lab.
[DOC File]Molar Mass - jdenuno
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Place 1.0 mL KHP into 150 mL beaker (Note: 1.0 mL KHP = 1.02 g KHP) Add 80—90 mL distilled water to beaker and stir with pipet. Add 10—20 mL distilled water to beaker so volume is approximately 100 mL and stir. Place 2.0 mL of KHP solution into 15 mL beaker, using the graduated pipet. Drop about 5 mm phenolphthalein test paper into the 15 ...
[DOC File]DILUTIONS AND STANDARDS
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In the second tube 2 mL of the first dilution was added to 2 mL of saline: 1/4 x 2/4 or 1/4 x 1/2 = 1/8 in 2nd tube . By transferring 2 mL of dilution from one tube to a second tube containing 2 mL of saline, and continuing to do so, this is actually making a 1:2 serial dilution. PROBLEMS: 1. You made a …
[DOC File]Molarity Worksheet #1
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What is the molarity? 214.2g OsF3 x 1 mol OsF3 = 12.9 M OsF3. 0.0673 L soln 247.23g OsF3. Calculate the molarity if a flask contains 1.54 moles potassium sulfate in 125 ml of solution. 1.54 mol K2SO4 = 12.3 M K2SO4. 0.125 L soln. A chalice contains 36.45 grams ammonium chlorite in 2.36 liters of solution - calculate the molarity.
[DOC File]CHEMISTRY 110 - Dr
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Molarity of HCl = (3.377 mmoles)/(100.00 mL) = 3.377 mM = 0.003377 M Student A is more accurate. (5 points) Are the results (titration volumes) obtained by the two students significantly different at the 95% confidence level (Given: Sspooled = 0.18)?
[DOC File]Calculations
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If you added 0.5 mL of 0.01 M glucose to a final volume of 20 mL what would be the concentration of the glucose in the diluted solution? Rather than reaching for the formula and the calculator, let’s use the principles above. A 0.01 M solution is equivalent to 10 mM and contains 10 mmol/L or 10 mol/mL ( 5 mol in 0.5 mL.
[DOC File]Acid-Base Titration
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7. “[ENTER] volume (mL)” should appear on the calculator’s display. This display is asking you to enter the amount , in mL, of NaOH you have added to the acid in the beaker. You have NOT added any NaOH from the buret to the acid, therefore, type 0 for volume of NaOH added. Press [ENTER]. 8. The calculator now displays a Data Collection menu.
[DOCX File]Stoichiometry Practice Worksheet
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Find the molarity of the following solutions: 1)0.5 moles of sodium chloride is dissolved to make 0.05 liters of solution. 2)0.5 grams of sodium chloride is dissolved to make 0.05 liters of solution. 3)0.5 grams of sodium chloride is dissolved to make 0.05 mL of solution. 4)734 grams of lithium sulfate are dissolved to make 2500 mL of solution.
[DOC File]Titration of Aspirin
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Show your calculations for the molarity of the NaOH from each of the three standardizations. Show your calculation for the average molarity of the NaOH based on the standardization. Show your calculations for the mass of aspirin that reacted in each of the two trials based on the amount of NaOH used.
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