Orbital period calculation
[DOC File]Planetary Orbit Simulator – Student Guide
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The Kepler's 3rd Law tab shows the calculation of period squared (P2) and the average orbital distance cubed (a3). The location of the simulated planet on a period vs. semimajor axis plot is shown. The plot can be displayed as a linear plot or a logarithmic plot.
[DOC File]MEASURING THE MASS OF JUPITER - Gettysburg College
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Example calculation: If the RMS reads 6.13275E+02, record 6.13E+02. ... [1 pt] What is the ratio of Europa’s orbital period to Io’s orbital period? If you got the right answers, this ratio should be a “nice” number that plays a large role in the volcanic activity on Io and, along with the Ganymede/Europa ratio, is also related to why ...
[DOC File]Calculate the Mass of the Milky Way Galaxy
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Orbital Period of the Sun about the Center of the Milky Way . 2.5E8 years for the Sun to orbit once about the center of the Milky Way Galaxy. Time squared = (2.5E8)^2 = 6.25E16. Newton’s form of Kepler’s Third Law. Mass = (distance)^3 divided by (time)^2. M=(18.7E8)^3 / (2,5E8)^2.
[DOC File]What is the moon's orbital period
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SYNODIC PERIOD The moon's synodic (pronounced "si nod ik") period is the time it takes it to go from full moon to full moon. This is longer than a synodic month because the Earth has advanced a little ( 360 degrees / 365.25 days per year = 0.9856 degrees per day) in its orbit around the sun.
[DOC File]Computer Simulation
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Besides number of cells per footprint, this module also takes care the calculation of the distance from satellite to the center of an edge cell, orbital period, and duration of a beam over a center cell for use in later modules. To find the distance from satellite to the center of edge cell, (25) β3 is the earth centered angle corresponding to α3
[DOCX File]Activity 3.2.5 Orbital Mechanics Modeling
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Option 2 (Orbital Tuner as a executable application) Orbit Tuner application. Orbit Tuner Java Script folder. Procedure. Determine the inclination and period of the satellite which produced the ground trace below. Show all calculations. Determine the inclination and period of the satellite which produced the ground trace below. Show all ...
[DOC File]ASTR 217 - Wenatchee Valley College
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The orbital period (P) is the length of time it takes to complete one orbit around the Sun. The distance from the Sun (a) is the semi-major axis of a planet’s elliptical orbit. Using years for time units and AU for distance units, Kepler’s third law becomes, “The period of a planet (in years), squared, equals the semi-major axis of the ...
[DOC File]A Practical use for Kepler’s laws:
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= orbital period of moon (in sec.) Jupiter’s mass is immense compared to the mass of its moons. The moons are only a tiny fraction of the planet’s mass, therefore we can estimate that the total mass of the system is close to Jupiter’s actual mass, and eliminate the moon’s mass from the equation.
[DOC File]SIERRA COLLEGE OBSERVATIONAL ASTRONOMY
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Table 2: Orbital Periods II. Orbital Period ÷ Io Orbital Period Orbital Period (seconds) Io Europa Ganymede Callisto Sample calculation #1—hhh:mm format. Io or Europa. Suppose for Io you clicked the 1-Hour advance button 17 times, and the 10-Min advance button 5 times. Then. Orbital time (hhh:mm) = 17 h + (5 x 10 min) = 17 h 50 min = 17:50
[DOCX File]northstarscience.weebly.com
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Click the “Additional data” display to find the orbital radius and period of each planet. Complete the first 2 empty columns of the chart in Observation question 5. Answer Observation question 6. Kepler discovered an interesting relationship between the cube of each planet’s orbital radius and the square of its period.
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