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[DOC File]Lab Math
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Common units for concentration measurements include mol/L, mmol/L, mg/L, mg/dL, and μg/mL. Others are also used. You need to be able to convert between these measurements readily. (Note that concentrations in mol/L are also called molar, and abbreviated M. A 2.5 mM solution, contains 2.5 mmol/L) Examples:
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[DOC File]AP Chemistry
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1.25 mol O2 x 2 mol Fe2O3/3 mol O2 = 0.833 mol Fe2O3 0.670 mol Fe2O3 x 160 g Fe2O3/1 mol Fe2O3 = 107 g Fe2O3 35 0.250 L x 0.127 mol/1 L x 74.1 g/1 mol = 2.35 g Add powder to 200 mL of water, dissolve, and then add water to bring the volume to 250. mL.
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[DOC File]Concentration and Dilution Lab
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M = mol CuSO4 / L. Show your work in the space provided below. (3 marks) Compare your solution with the stock solution at the front of the class. Comment on the colour of your solution compared to the colour of the stock solution. (1 mark) Dilution Procedure. Using a 20 ml transfer pipette transfer 20ml of your original solution into a clean flask.
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[DOC File]Agency Contract Data Conversion Guide
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Open Purchase Orders Conversion Guide January 2010 Open Purchase Orders Conversion Overview. Open purchase orders will exist in the legacy systems currently in …
ml to moles

[DOCX File]AP Chemistry
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c.The molecular mass of the compound is approximately 300 g/mol. Determine the molecular formula. 24. 75.0 g of Fe reacts with 11.5 L of O 2 ( d = 3.48 g/L) according to …
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[DOC File]Molarity Notes – H
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The concentration of this solution is one molar (1.00 mol/L or 1.00M) Example 2: What is the concentration of a solution made by dissolving 175.5g of NaCl in enough water to make 2.00 liters of solution? Answer: 175.5g NaCl 1 mol = 3.00 mol of salt dissolved in 2.00 liters so 3.00mol = 1.50 M …
mass to mole conversion formula

[DOC File]Chapter 12 – Kinetics
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The reaction A ( B + C is known to be zero order in A with a rate constant of 5.0 x 10–2 mol/L × s at 25°C. An experiment was run at 25°C where [A]0 = 1.0 x 10–3 M. 23) The integrated rate law is
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[DOCX File]St. Johns County School District
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What volume of 0.100 M NaOH is required to neutralize 25.00 ml of 0.110 M H 2 SO 4? *(There are 2 mol H 3 O+ for every 1 mol H 2 SO 4) 55.0. What volume of 0.100 M NaOH is required to neutralize 25.00 ml of 0.150 M HCl? 37.5 m. L. If 35.40 ml of 1.000 M HCl is neutralized by 67.30 ml of NaOH, what is the molarity of the NaOH solution?
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[DOCX File]Stoichiometry Practice Worksheet
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Using the equation M = mol/L, this translates to 0.135 L of 0.100 M . HCl. b)If I combined 15.0 grams of calcium hydroxide with 75.0 mL of 0.500 M HCl, how many grams of calcium chloride would be formed? 2.08 grams. c)What is the limiting reagent from the reaction in problem #3? HCl.
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[DOC File]Chapter 13 worksheet #1
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Consider a 0.300 M solution of NaOH? Calculate the molality of NaOH. (Assume the density of the solution is the same as the density of pure water.) Assume that you have 1 L of solution: Mass of water = mass of solution – mass of NaOH = 1000 g – (0.300 mol)(40 g/mol) = 1000 g – 12 g = 988 g. Molality = 0.300 mol/0.988 kg = 0.304 m
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M to mol