Stoichiometry worksheet and key

    • [DOC File]Worksheet for Basic Stoichiometry

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      Worksheet for Basic Stoichiometry. Part 1: Mole ←→ Mass Conversions. Convert the following number of moles of chemical into its corresponding mass in grams. 1. 0.436 moles of ammonium chloride. 2. 2.360 moles of lead (II) oxide. 3. 0.031 moles of aluminum iodide. 4. 1.077 moles of magnesium phosphate. 5. 0.50 moles of calcium nitrate

      stoichiometry worksheet and key answers

    • [DOC File]CHAPTER 11: STOICHIOMETRY

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      Key Terms: stoichiometry. mole-mole problems. mass-mass problems. mass-volume problems. volume-volume problems. particle –particle problems. expected yield. actual yield. percent yield Directions: Use this information as a general reference tool to guide you through this unit. Don’t hesitate to ask your teacher for help!

      stoichiometry problems with answer key

    • [DOC File]Stoichiometry Worksheet - FREE Chemistry Materials ...

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      Chemistry: Supplemental Stoichiometry Problems. Directions: Solve each of the following problems. Assume excess of any reactant that isn’t mentioned, unless otherwise . specified. Show your work, including proper units, to earn full credit. 1. Given the balanced equation, show what the following molar ratios (i.e., the conversion factors ...

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    • [DOC File]WPHS - Walled Lake Consolidated Schools

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      Stoichiometry Worksheet 1 KEY. 1. Carbon disulfide is an important industrial solvent. It is prepared by the reaction of coke with sulfur dioxide: 5C(s) + 2SO2(g) -----> CS2(s) + 4CO(g) How many moles of CS2 form when 6.3 mol of C reacts? How many moles of carbon are needed to react with 7.24 moles of SO2. 2.

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    • [DOC File]WPHS - Region 14

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      Stoichiometry Worksheet 1 KEY. 1. Carbon disulfide is an important industrial solvent. It is prepared by the reaction of coke with sulfur dioxide: 5C(s) + 2SO2(g) -----> CS2(s) + 4CO(g) How many moles of CS2 form when 6.3 mol of C reacts? How many moles of carbon are needed to react with 7.24 moles of SO2. 2.

      stoichiometry problems worksheet and answers

    • [DOC File]Stoichiometry Worksheet

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      Stoichiometry Worksheet. In a combustion reaction, acetylene (C2H2) combines with oxygen to form carbon dioxide and water. Step 1: Write out the equation: ___ C2H2 + ___ O2 ( ___ CO2 + ___ H2O. 3.80 moles of oxygen are used up in the reaction. How many moles of …

      worksheet for basic stoichiometry key

    • [DOC File]Worksheet for Basic Stoichiometry

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      Chem_Ch 9 Stoichiometry Review. Remember the two roadmaps and how to use them. grams ↔ moles ↔ particles. grams ↔ moles ↔ moles ↔ grams . Remember to balance all equations. 1. The combustion of a sample of butane, C4H10 (lighter fluid), produced 2.46 grams of water. 2 C4H10 + 13O2 ( 8CO2 + 10H2O . a. How many moles of water formed? b.

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    • [DOCX File]Stoichiometry Practice Worksheet

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      Mole Conversions and Stoichiometry Review Worksheet. 1)Using the following equation: 2 NaOH + H. 2 SO 4 2 H 2 O + Na 2 SO. 4. How many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid (H. 2 SO 4)?. 2)Using the following equation: Pb(SO. 4) 2 + 4 LiNO 3 Pb(NO 3) 4 + 2 Li 2 SO. 4. How many …

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    • [DOC File]Stoichiometry: Mole to Mass Problems

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      Answers to Stoichiometry: Mole to Mass Problems. 1. Hydrogen gas can be produced through the following reaction. Mg(s) + 2HCl(aq) ( MgCl2(aq) + H2(g) How many grams of HCl are consumed by the reaction of 2.50 moles of magnesium? 182g HCl. What is the mass in grams of H2 gas when 4.0 moles of HCl is added to the reaction? 4.0g H2. 2.

      stoichiometry worksheet and key answers

    • [DOC File]Stoichiometry: Mole-Mole Problems

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      Answer Key. Stoichiometry: Mole-Mole Problems. N2 + 3H2 → 2NH3. How many moles of hydrogen are needed to completely react with 2.0 moles of nitrogen? 6.0 moles of hydrogen . 2. 2KClO3 → 2KCl + 3O2. How many moles of oxygen are produced by the decomposition of 6.0 moles of potassium chlorate? 9.0 moles of oxygen . Zn + 2HCl → ZnCl2 + H2

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